12=x(5-3)^2-4

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Solution for 12=x(5-3)^2-4 equation: 



12=x(5-3)^2-4

We move all terms to the left:

12-(x(5-3)^2-4)=0

We add all the numbers together, and all the variables

-(x2^2-4)+12=0

We get rid of parentheses

-x2^2+4+12=0

We add all the numbers together, and all the variables

-x2^2+16=0

We move all terms containing x to the left, all other terms to the right

-x2^2=-16

x=-16/1

x=-16

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